Physics

Work Calculator

Calculate work done by a force.

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THE NUMORIX GUIDE

How to use the Work Calculator

Last reviewed September 14, 2026

What this calculator does

The engine calculates mechanical work for a constant force as W = F*d*cos(theta), converting the entered angle from degrees to radians.

Formula and method

The engine calculates mechanical work for a constant force as W = F*d*cos(theta), converting the entered angle from degrees to radians. It also returns 0.5*F*d as a simplified kinetic helper field and F*d*sin(theta) as a potential-energy field, but the UI displays only Work and its kJ conversion.

Variables and inputs

Enter force in newtons, distance in meters, and the angle between force and displacement in degrees. The visible handler requires numeric, nonnegative force and distance but does not restrict the angle. Work is returned in joules and shown to four decimal places, with kJ shown separately.

Worked example

For F = 10 N, d = 5 m, and theta = 0 degrees, W = 10*5*cos(0) = 50 J, or 0.0500 kJ. The engine also returns 25 J in its simplified helper field and 0 J for its angle-based helper, but neither appears in the result card.

How to interpret the result

Work is energy transferred by the component of force along the displacement. Parallel force gives positive work, perpendicular force gives zero, and an opposing force can give negative work; the result is not determined by force magnitude alone.

Common mistakes to avoid

Use displacement rather than total path length, enter the force-displacement angle in degrees, and keep newtons and meters together for joules. Do not treat the engine's simplified extra fields as general kinetic- or potential-energy equations.

Assumptions and limitations

The formula assumes a constant force and straight displacement; a changing force requires an integral. The engine's extra kinetic- and potential-energy values are implementation shortcuts, not complete physics models, and the UI does not validate angle range, mass, velocity, or a reference height.

Sources and references

COMMON QUESTIONS

Frequently asked questions

What does a 90-degree force do to work?

cos(90 degrees) is zero, so a constant force perpendicular to displacement does no mechanical work in this model, even though it may change the direction of motion or create torque.

Why are the extra energy fields not shown?

The engine returns simplified helper values, but the current UI renders only the work result and a kJ conversion. They should not be interpreted as general kinetic- or potential-energy calculations.

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